nth_rewrite tactic

The tactic nth_rewrite and nth_rw are variants of rewrite and rw that only performs the nth possible rewrite.

def Mathlib.Tactic.nthRewriteSeq : Lean.ParserDescr

nth_rewrite is a variant of rewrite that only changes the nᵗʰ occurrence of the expression to be rewritten. nth_rewrite n [eq₁, eq₂,..., eqₘ] will rewrite the nᵗʰ occurrence of each of the m equalities eqᵢin that order. Occurrences are counted beginning with 1 in order of precedence.

For example,

example (h : a = 1) : a + a + a + a + a = 5 := by
  nth_rewrite 2 [h]
/-
a: ℕ
h: a = 1
⊢ a + 1 + a + a + a = 5
-/

Notice that the second occurrence of a from the left has been rewritten by nth_rewrite.

To understand the importance of order of precedence, consider the example below

example (a b c : Nat) : (a + b) + c = (b + a) + c := by
  nth_rewrite 2 [Nat.add_comm] -- ⊢ (b + a) + c = (b + a) + c

Here, although the occurrence parameter is 2, (a + b) is rewritten to (b + a). This happens because in order of precedence, the first occurrence of _ + _ is the one that adds a + b to c. The occurrence in a + b counts as the second occurrence.

If a term t is introduced by rewriting with eqᵢ, then this instance of t will be counted as an occurrence of t for all subsequent rewrites of t with eqⱼ for j > i. This behaviour is illustrated by the example below

example (h : a = a + b) : a + a + a + a + a = 0 := by
  nth_rewrite 3 [h, h]
/-
a b: ℕ
h: a = a + b
⊢ a + a + (a + b + b) + a + a = 0
-/

Here, the first nth_rewrite with h introduces an additional occurrence of a in the goal. That is, the goal state after the first rewrite looks like below

/-
a b: ℕ
h: a = a + b
⊢ a + a + (a + b) + a + a = 0
-/

This new instance of a also turns out to be the third occurrence of a. Therefore, the next nth_rewrite with h rewrites this a.

Equations

• One or more equations did not get rendered due to their size.

def Mathlib.Tactic.evalNthRewriteSeq : Lean.Elab.Tactic.Tactic

nth_rewrite is a variant of rewrite that only changes the nᵗʰ occurrence of the expression to be rewritten. nth_rewrite n [eq₁, eq₂,..., eqₘ] will rewrite the nᵗʰ occurrence of each of the m equalities eqᵢin that order. Occurrences are counted beginning with 1 in order of precedence.

For example,

example (h : a = 1) : a + a + a + a + a = 5 := by
  nth_rewrite 2 [h]
/-
a: ℕ
h: a = 1
⊢ a + 1 + a + a + a = 5
-/

Notice that the second occurrence of a from the left has been rewritten by nth_rewrite.

To understand the importance of order of precedence, consider the example below

example (a b c : Nat) : (a + b) + c = (b + a) + c := by
  nth_rewrite 2 [Nat.add_comm] -- ⊢ (b + a) + c = (b + a) + c

Here, although the occurrence parameter is 2, (a + b) is rewritten to (b + a). This happens because in order of precedence, the first occurrence of _ + _ is the one that adds a + b to c. The occurrence in a + b counts as the second occurrence.

If a term t is introduced by rewriting with eqᵢ, then this instance of t will be counted as an occurrence of t for all subsequent rewrites of t with eqⱼ for j > i. This behaviour is illustrated by the example below

example (h : a = a + b) : a + a + a + a + a = 0 := by
  nth_rewrite 3 [h, h]
/-
a b: ℕ
h: a = a + b
⊢ a + a + (a + b + b) + a + a = 0
-/

Here, the first nth_rewrite with h introduces an additional occurrence of a in the goal. That is, the goal state after the first rewrite looks like below

/-
a b: ℕ
h: a = a + b
⊢ a + a + (a + b) + a + a = 0
-/

This new instance of a also turns out to be the third occurrence of a. Therefore, the next nth_rewrite with h rewrites this a.

Equations

• One or more equations did not get rendered due to their size.

def Mathlib.Tactic.nthRwSeq : Lean.ParserDescr

nth_rw is a variant of rw that only changes the nᵗʰ occurrence of the expression to be rewritten. Like rw, and unlike nth_rewrite, it will try to close the goal by trying rfl afterwards. nth_rw n [eq₁, eq₂,..., eqₘ] will rewrite the nᵗʰ occurrence of each of the m equalities eqᵢin that order. Occurrences are counted beginning with 1 in order of precedence. For example,

example (h : a = 1) : a + a + a + a + a = 5 := by
  nth_rw 2 [h]
/-
a: ℕ
h: a = 1
⊢ a + 1 + a + a + a = 5
-/

Notice that the second occurrence of a from the left has been rewritten by nth_rewrite.

To understand the importance of order of precedence, consider the example below

example (a b c : Nat) : (a + b) + c = (b + a) + c := by
  nth_rewrite 2 [Nat.add_comm] -- ⊢ (b + a) + c = (b + a) + c

Here, although the occurrence parameter is 2, (a + b) is rewritten to (b + a). This happens because in order of precedence, the first occurrence of _ + _ is the one that adds a + b to c. The occurrence in a + b counts as the second occurrence.

If a term t is introduced by rewriting with eqᵢ, then this instance of t will be counted as an occurrence of t for all subsequent rewrites of t with eqⱼ for j > i. This behaviour is illustrated by the example below

example (h : a = a + b) : a + a + a + a + a = 0 := by
  nth_rw 3 [h, h]
/-
a b: ℕ
h: a = a + b
⊢ a + a + (a + b + b) + a + a = 0
-/

Here, the first nth_rw with h introduces an additional occurrence of a in the goal. That is, the goal state after the first rewrite looks like below

/-
a b: ℕ
h: a = a + b
⊢ a + a + (a + b) + a + a = 0
-/

This new instance of a also turns out to be the third occurrence of a. Therefore, the next nth_rw with h rewrites this a.

Further, nth_rw will close the remaining goal with rfl if possible.

Equations

• One or more equations did not get rendered due to their size.